General Table Completion using a Bayesian Nonparametric Model

Authors: Isabel Valera, Zoubin Ghahramani

NeurIPS 2014 | Conference PDF | Archive PDF | Plain Text | LLM Run Details

Reproducibility Variable Result LLM Response
Research Type Experimental Finally, our experiments over five real databases show that the proposed approach provides more robust and accurate estimates than the standard IBP and the Bayesian probabilistic matrix factorization with Gaussian observations.
Researcher Affiliation Academia Isabel Valera Department of Signal Processing and Communications University Carlos III in Madrid ivalera@tsc.uc3m.es Zoubin Ghahramani Department of Engineering University of Cambridge zoubin@eng.cam.ac.uk
Pseudocode Yes Algorithm 1 Inference Algorithm.
Open Source Code Yes An efficient C-code implementation for Matlab of the proposed table completion tool is also released on the authors website.
Open Datasets Yes Statlog German credit dataset [5]... Dataset available on: http://archive.ics.uci.edu/ml/datasets.html
Dataset Splits No The paper discusses average test log-likelihood per missing datum but does not provide specific details on train/validation/test dataset splits, such as percentages, sample counts, or cross-validation setup.
Hardware Specification No The paper does not provide specific hardware details (exact GPU/CPU models, processor types, or memory amounts) used for running its experiments.
Software Dependencies No An efficient C-code implementation for Matlab of the proposed table completion tool is also released on the authors website.
Experiment Setup Yes For the GIBP, we consider for the real positive and the count data the following transformation, that maps from the real numbers to the real positive numbers, f(x) = log(exp(wx) + 1), where w is a user hyper-parameter.For the BPMF model, we have used different numbers of latent features (in particular, 10, 20 and 50), although we only show the best results for each database, specifically, K = 10 for the NESARC and the wine databases, and K = 50 for the remainder.